Questions of Quantitative Aptitude for OLETs
1. A sum of ₹12,000 is divided among A, B, and C such that A gets twice as much as B, and B gets
1.5 times as much as C. How much does C get?
₹2,000
₹3,000
₹4,000
₹6,000
2. The length of a rectangle is increased by 20%, and the breadth is decreased by 10%. What is the percentage change in the area?
8% increase
10% increase
8% decrease
10% decrease
3. A pipe can fill a tank in 8 hours, while another pipe can empty it in 12 hours. If both pipes are opened simultaneously, how long will it take to fill the tank?
20 hours
24 hours
30 hours
32 hours
4. Solve for ( x ):
3x/4 +5 = 17
12
16
20
24
2
5. If the difference between the compound interest and simple interest on a sum for 2 years at 10% per annum is ₹50, find the sum.
₹1,000
₹5,000
₹2,500
₹10,000
6. A man travels 25% of his journey by train, 50% by bus, and the remaining 60 km by foot. What is the total distance of the journey?
120 km
180 km
240 km
300 km
7. The ratio of the ages of A and B is 5:7. After 6 years, the ratio becomes 3:4. What is B’s current age?
28 years
35 years
42 years
49 years
8. Two numbers are in the ratio 3:4. If their LCM is 240, find their HCF.
10
15
20
25
9. A sphere and a cube have the same surface area. If the radius of the sphere is 7 cm, find the side of the cube.
14 cm
21 cm
3
28 cm
35 cm
10. A man rows downstream at 15 km/h and upstream at 10 km/h. What is the speed of the current?
2.5 km/h
5 km/h
7.5 km/h
10 km/h
11. The product of two consecutive even numbers is 224. Find the numbers.
12 and 14
14 and 16
16 and 18
18 and 20
12. A sum of ₹5,000 becomes ₹6,050 in 2 years at simple interest. Find the rate of interest per annum.
8%
9%
10%
12%
13. If a + b = 10 and ab = 21 , find the value of a^2+b^2 ?
29
49
79
99
14. A boat covers 40 km upstream in 8 hours and the same distance downstream in 4 hours. Find the speed of the boat in still water.
5 km/h
4
6 km/h
7 km/h
8 km/h
15. If the perimeter of a square is 56 cm, find the area of the square.
49 cm²
196 cm²
256 cm²
324 cm²
Answers and Solutions
1. Answer: (B) ₹3,000 Solution:
Let C’s share = ₹x.
Then B’s share = 1.5x, and A’s share = 2 × 1.5x = 3x.
Total: x + 1.5x + 3x = ₹12,000
5.5x = ₹12,000 x = ₹12,000 / 5.5 = ₹3,000
So, C gets ₹3,000.
2. Answer: (A) 8% increase
Solution:
Initial area = l * b
New length = l + 20% l = 1.2 l,
New breadth = b – 10 %b = 0.9 b
New area = 1.2l * 0.9b = 1.08lb .
Percentage change = ( 1.08lb – lb = 0.08lb ). therefore 8% increase.
3. Answer: (B) 24 hours
Solution:
Work done by the filling pipe in 1 hour = ⅛
Work done by the emptying pipe in 1 hour = -1/12
Net work done in 1 hour = 1/8 – 1/12 = 1/24
Time to fill = 1 / (1/24) = 24 hours.
4. Answer: (B) 16
Solution:
3x/4 + 5 = 17 3x/4= 17-5 = 12 x = 12* 4/3 = 16
5. Answer: (C) ₹2,500 Solution:
Difference between compound and simple interest = Principal * (R/100)^2
50 = P * (10/100)^2
50 = P * 0.01
P = 50 / 0.01 = ₹2,500
6. Answer: (B) 180 km Solution:
Let total distance = x
Distance by train = 25 %x = 0.25x
Distance by bus = 50 %x = 0.5x
Distance by foot = 60 km
0.25x + 0.5x + 60 = x
0.75x + 60 = x 60 = 0.25x x = 240 km
7. Answer: (C) 42 years
Solution:
Let A’s and B’s ages be 5x and 7x
After 6 years:
(5x + 6)/ (7x + 6) = 3/4 x= 6
7
B’s current age = 7x = 42
8. Answer: (C) 20
Solution:
Let the numbers be 3k and 4k LCM = 12k , so 12k = 240 k = 20
HCF = k = 20
9. Answer: (A) 14 cm
Solution:
Surface area of sphere = 4πr^2
4π (7)^2 = 616
Surface area of cube = 6a^2 ,so 6a^2 = 616 a^2 = 616 / 6 = 102.67 a= √102.67 ~ 14 cm 10.
10. Answer: (A) 2.5 km/h
Solution:
Speed of current = Downstream speed – Upstream speed/ 2
= 15-10/ 2= 2.5 km/h
11. Answer: (B) 14 and 16
Solution:
Let numbers be x and x+2 x(x + 2) = 224 x^2 + 2x – 224 = 0 Solve: (x + 16)(x – 14) = 0 x = 14 , so numbers are 14 and 16. 8
12. Answer: (C) 10%
Solution:
Simple Interest = 6,050 – 5,000 = ₹1,050
SI = P RT/100
1,050 = 5,000 R 2/100
R= 10%
13. Answer: (A) 29
Solution: a + b = 10 , ab = 21 a^2 + b^2 = (a + b)^2 – 2ab
= 10^2 – 2(21) = 100 – 42 = 29
14. Answer: (C) 7 km/h
Solution:
Upstream speed = 40/8 = 5 km/h
Downstream speed = 40/4 = 10 km/h
Speed in still water = Upstream speed + Downstream speed/ 2
= 5+10/2
= 7 km/h
15. Answer: (B) 196 cm² Solution:
Perimeter = 4* Side = 56
Side = 14 cm
Area = 14*14= 196 cm^2